(3x+5)(x^2+4x-2)=0

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Solution for (3x+5)(x^2+4x-2)=0 equation: 


Simplifying
(3x + 5)(x2 + 4x + -2) = 0

Reorder the terms:
(5 + 3x)(x2 + 4x + -2) = 0

Reorder the terms:
(5 + 3x)(-2 + 4x + x2) = 0

Multiply (5 + 3x) * (-2 + 4x + x2)
(5(-2 + 4x + x2) + 3x * (-2 + 4x + x2)) = 0
((-2 * 5 + 4x * 5 + x2 * 5) + 3x * (-2 + 4x + x2)) = 0
((-10 + 20x + 5x2) + 3x * (-2 + 4x + x2)) = 0
(-10 + 20x + 5x2 + (-2 * 3x + 4x * 3x + x2 * 3x)) = 0
(-10 + 20x + 5x2 + (-6x + 12x2 + 3x3)) = 0

Reorder the terms:
(-10 + 20x + -6x + 5x2 + 12x2 + 3x3) = 0

Combine like terms: 20x + -6x = 14x
(-10 + 14x + 5x2 + 12x2 + 3x3) = 0

Combine like terms: 5x2 + 12x2 = 17x2
(-10 + 14x + 17x2 + 3x3) = 0

Solving
-10 + 14x + 17x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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